John

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)

Total Submission(s): 4704    Accepted Submission(s): 2720

Problem Description

Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.

Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.

 

 

Input

The first line of input will contain a single integer T – the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N – the amount of different M&M colors in a box. Next line will contain N integers Ai, separated by spaces – amount of M&Ms of i-th color.

Constraints:

1 <= T <= 474,

1 <= N <= 47,

1 <= Ai <= 4747

 

 

Output

Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.

 

 

Sample Input

2 3 3 5 1 1 1

 

 

Sample Output

John Brother

 

 

Source

 

 

1 #include 
      
        2 using namespace std; 3  4 int main() 5 { 6     int t; 7     int n; 8     int a; 9     int i;10     int sum, ones;11 12     scanf("%d", &t);13 14     while (t--) {15         scanf("%d", &n);16         sum = 0, ones = 0;17         for (i = 0; i < n; ++i) {18             scanf("%d", &a);19             sum ^= a;20             if (a == 1) {21                 ++ones;22             }23         }24 25         //win : t0, s1, s226         //lose : s0, t227         if (sum == 0) {
    //t28             if (n - ones == 0) {
    //t029                 printf("John\n");30             } else {
    //t231                 printf("Brother\n");32             }33         } else {
    //s34             if (n - ones == 0) {
    //s035                 printf("Brother\n");36             } else {
    //s1, s237                 printf("John\n");38             }39         }40     }41 42     return 0;43 }